Q tensor

In physics, $\mathbf {Q}$ tensor is an orientational order parameter that describes uniaxial and biaxial nematic liquid crystals and vanishes in the isotropic liquid phase. The $\mathbf {Q}$ tensor is a second-order, traceless, symmetric tensor and is defined by

$\mathbf {Q} =S\left(\mathbf {n} \mathbf {n} -{\frac {1}{3}}\mathbf {I} \right)+P\left(\mathbf {m} \mathbf {m} -{\frac {1}{3}}\mathbf {I} \right)$

where $S=S(T)$ and $P=P(T)$ are scalar order parameters, $(\mathbf {n} ,\mathbf {m} )$ are the two directors of the nematic phase and $T$ is the temperature; in uniaxial liquid crystals, $P=0$. The componenets of the tensor are

$Q_{ij}=S\left(n_{i}n_{j}-{\frac {1}{3}}\delta _{ij}\right)+P\left(m_{i}m_{j}-{\frac {1}{3}}\delta _{ij}\right)$

The states with directors $\mathbf {n}$ and $-\mathbf {n}$ are physically equivalent and similarly the states with directors $\mathbf {m}$ and $-\mathbf {m}$ are physically equivalent.

The $\mathbf {Q}$ tensor can always be diagonalized,

$\mathbf {Q} ={\begin{pmatrix}-{\frac {1}{2}}(S+P)&0&0\\0&-{\frac {1}{2}}(S-P)&0\\0&0&S\\\end{pmatrix}}$

The following are the invariants of the $\mathbf {Q}$ tensor

$\delta =Q_{ij}Q_{ij}={\frac {1}{2}}(3S^{2}+P^{2}),\quad \Delta =Q_{ij}Q_{jk}Q_{ki}={\frac {3}{4}}S(S^{2}-P^{2}).$

It can be shown that $\delta ^{3}\geq 6\Delta ^{2}.$

Uniaxial nematics

In uniaxial nematic liquid crystals, $P=0$ and therefore the $\mathbf {Q}$ tensor reduces to

$\mathbf {Q} =S\left(\mathbf {n} \mathbf {n} -{\frac {1}{3}}\mathbf {I} \right).$

The scalar order parameter is defined as follows. If $\theta _{\mathrm {mol} }$ represents the angle between the axis of a nematic molecular and the director axis $\mathbf {n}$, then

$S=\langle P_{2}(\cos \theta _{\mathrm {mol} })\rangle ={\frac {1}{2}}\langle 3\cos ^{2}\theta _{\mathrm {mol} }-1\rangle ={\frac {1}{2}}\int (3\cos ^{2}\theta _{\mathrm {mol} }-1)f(\theta _{\mathrm {mol} })d\Omega$

where $\langle \cdot \rangle$ denotes the ensemble average of the orientational angles calculated with respect to the distribution function $f(\theta _{\mathrm {mol} })$ and $d\Omega =\sin \theta _{\mathrm {mol} }d\theta _{\mathrm {mol} }d\phi _{\mathrm {mol} }$ is the solid angle. The distribution function must necessarily satisfy the condition $f(\theta _{\mathrm {mol} }+\pi )=f(\theta _{\mathrm {mol} })$ since the directors $\mathbf {n}$ and $-\mathbf {n}$ are physically equivalent.

The range for $S$ is given by $-1/2\leq S\leq 1$, with $S=1$ representing the perfect alignment of all molecules along the director and $S=0$ representing the comeplete random alignment (isotropic) of all molecules with respect to the director; the $S=-1/2$ case indicates that all moelcules are aligned perpendicular to the director axis although such nematics are rare or hard to synthesize.

See also

• Landau–de Gennes theory