1826 Ohio gubernatorial election
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The 1826 Ohio gubernatorial election was held on 10 October 1826, in order to elect the Governor of Ohio. National Republican candidate and former Acting Governor Allen Trimble defeated Democratic-Republican candidates Alexander Campbell, Benjamin Tappan and John Bigger.[1]
General election[edit]
On election day, 10 October 1826, National Republican candidate Allen Trimble won the election by a margin of 66,710 votes against his foremost opponent Democratic-Republican candidate Alexander Campbell, thereby gaining National Republican control over the office of Governor. Trimble was sworn in as the 10th Governor of Ohio on 19 December 1826.[2]
Results[edit]
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| National Republican | Allen Trimble | 71,475 | 84.35% | |
| Democratic-Republican | Alexander Campbell | 4,765 | 5.62% | |
| Democratic-Republican | Benjamin Tappan | 4,192 | 4.95% | |
| Democratic-Republican | John Bigger | 4,114 | 4.86% | |
| Scattering | 187 | 0.22% | ||
| Total votes | 84,733 | 100.00% | ||
| National Republican gain from Democratic-Republican | ||||
References[edit]
- ^ "Allen Trimble". National Governors Association. Retrieved 10 May 2024.
- ^ "OH Governor". ourcampaigns.com. 18 February 2005. Retrieved 10 May 2024.
Categories:
- 1826 Ohio elections
- Ohio gubernatorial elections
- 1826 United States gubernatorial elections
- 1826 in Ohio
- October 1826 events
- 1820s in Ohio
- 1820s Ohio elections
- 1826 elections
- 1826 elections in North America
- 1826 elections in the United States
- United States gubernatorial elections in the 1820s
- Government of Ohio